-2x^2-13x+20=-3x^2

Solution for -2x^2-13x+20=-3x^2 equation:

-2x^2-13x+20=-3x^2

We move all terms to the left:

-2x^2-13x+20-(-3x^2)=0

We get rid of parentheses

-2x^2+3x^2-13x+20=0

We add all the numbers together, and all the variables

x^2-13x+20=0

a = 1; b = -13; c = +20;
Δ = b2-4ac
Δ = -132-4·1·20
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{89}}{2*1}=\frac{13-\sqrt{89}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{89}}{2*1}=\frac{13+\sqrt{89}}{2}
$